(4x+32)(8x-72)=0

Solution for (4x+32)(8x-72)=0 equation:

(4x+32)(8x-72)=0

We multiply parentheses ..

(+32x^2-288x+256x-2304)=0

We get rid of parentheses

32x^2-288x+256x-2304=0

We add all the numbers together, and all the variables

32x^2-32x-2304=0

a = 32; b = -32; c = -2304;
Δ = b2-4ac
Δ = -322-4·32·(-2304)
Δ = 295936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{295936}=544$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-544}{2*32}=\frac{-512}{64}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+544}{2*32}=\frac{576}{64}
=9
$