(7x-35+)(2x+15)=180

Solution for (7x-35+)(2x+15)=180 equation:

(7x-35+)(2x+15)=180

We move all terms to the left:

(7x-35+)(2x+15)-(180)=0

We add all the numbers together, and all the variables

(+7x)(2x+15)-180=0

We multiply parentheses ..

(+14x^2+105x)-180=0

We get rid of parentheses

14x^2+105x-180=0

a = 14; b = 105; c = -180;
Δ = b2-4ac
Δ = 1052-4·14·(-180)
Δ = 21105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{21105}=\sqrt{9*2345}=\sqrt{9}*\sqrt{2345}=3\sqrt{2345}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-3\sqrt{2345}}{2*14}=\frac{-105-3\sqrt{2345}}{28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+3\sqrt{2345}}{2*14}=\frac{-105+3\sqrt{2345}}{28}
$