(X+12)(2x-8)=0

Solution for (X+12)(2x-8)=0 equation:

(X+12)(2X-8)=0

We multiply parentheses ..

(+2X^2-8X+24X-96)=0

We get rid of parentheses

2X^2-8X+24X-96=0

We add all the numbers together, and all the variables

2X^2+16X-96=0

a = 2; b = 16; c = -96;
Δ = b2-4ac
Δ = 162-4·2·(-96)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-32}{2*2}=\frac{-48}{4}
=-12
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+32}{2*2}=\frac{16}{4}
=4
$