(7x-3/3)=(3x-4/8)

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Solution for (7x-3/3)=(3x-4/8) equation:



(7x-3/3)=(3x-4/8)
We move all terms to the left:
(7x-3/3)-((3x-4/8))=0
We add all the numbers together, and all the variables
(7x-1)-((+3x-4/8))=0
We get rid of parentheses
7x-((+3x-4/8))-1=0
We multiply all the terms by the denominator
7x*8))-((+3x-4-1*8))=0
We add all the numbers together, and all the variables
7x*8))-((3x-12))=0
We add all the numbers together, and all the variables
7x*8))-((3x=0
Wy multiply elements
56x^2=0
a = 56; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·56·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{112}=0$

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