-3k+33=3(k-5)

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Solution for -3k+33=3(k-5) equation: 



-3k+33=3(k-5)

We move all terms to the left:

-3k+33-(3(k-5))=0



We calculate terms in parentheses: -(3(k-5)), so:

3(k-5)

We multiply parentheses

3k-15

Back to the equation:

-(3k-15)



We get rid of parentheses

-3k-3k+15+33=0

We add all the numbers together, and all the variables

-6k+48=0

We move all terms containing k to the left, all other terms to the right

-6k=-48

k=-48/-6

k=+8

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