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(7x-3)(6x+7)=0
We multiply parentheses ..
(+42x^2+49x-18x-21)=0
We get rid of parentheses
42x^2+49x-18x-21=0
We add all the numbers together, and all the variables
42x^2+31x-21=0
a = 42; b = 31; c = -21;
Δ = b2-4ac
Δ = 312-4·42·(-21)
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4489}=67$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-67}{2*42}=\frac{-98}{84} =-1+1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+67}{2*42}=\frac{36}{84} =3/7 $
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