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10x^2=100
We move all terms to the left:
10x^2-(100)=0
a = 10; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·10·(-100)
Δ = 4000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4000}=\sqrt{400*10}=\sqrt{400}*\sqrt{10}=20\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{10}}{2*10}=\frac{0-20\sqrt{10}}{20} =-\frac{20\sqrt{10}}{20} =-\sqrt{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{10}}{2*10}=\frac{0+20\sqrt{10}}{20} =\frac{20\sqrt{10}}{20} =\sqrt{10} $
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