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(7x-3)(4x+8)=0
We multiply parentheses ..
(+28x^2+56x-12x-24)=0
We get rid of parentheses
28x^2+56x-12x-24=0
We add all the numbers together, and all the variables
28x^2+44x-24=0
a = 28; b = 44; c = -24;
Δ = b2-4ac
Δ = 442-4·28·(-24)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-68}{2*28}=\frac{-112}{56} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+68}{2*28}=\frac{24}{56} =3/7 $
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