1/3(x-4)+5/6(x+3)=x+1

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Solution for 1/3(x-4)+5/6(x+3)=x+1 equation: 



1/3(x-4)+5/6(x+3)=x+1

We move all terms to the left:

1/3(x-4)+5/6(x+3)-(x+1)=0



Domain of the equation: 3(x-4)!=0

x∈R





Domain of the equation: 6(x+3)!=0

x∈R



We get rid of parentheses

1/3(x-4)+5/6(x+3)-x-1=0

We calculate fractions


-x+(6xx/(3(x-4)*6(x+3))+(15xx/(3(x-4)*6(x+3))-1=0

We can not solve this equation

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