(7x-2)+(x+5)+(3x+1)=180

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Solution for (7x-2)+(x+5)+(3x+1)=180 equation: 



(7x-2)+(x+5)+(3x+1)=180

We move all terms to the left:

(7x-2)+(x+5)+(3x+1)-(180)=0

We get rid of parentheses

7x+x+3x-2+5+1-180=0

We add all the numbers together, and all the variables

11x-176=0

We move all terms containing x to the left, all other terms to the right

11x=176

x=176/11

x=16

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