(2x-4)(-x+3)=0

Solution for (2x-4)(-x+3)=0 equation:

(2x-4)(-x+3)=0

We add all the numbers together, and all the variables

(2x-4)(-1x+3)=0

We multiply parentheses ..

(-2x^2+6x+4x-12)=0

We get rid of parentheses

-2x^2+6x+4x-12=0

We add all the numbers together, and all the variables

-2x^2+10x-12=0

a = -2; b = 10; c = -12;
Δ = b2-4ac
Δ = 102-4·(-2)·(-12)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2}{2*-2}=\frac{-12}{-4}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2}{2*-2}=\frac{-8}{-4}
=+2
$