(7x-2)+(7x-2)+(2x+4)=(3x+3)4

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Solution for (7x-2)+(7x-2)+(2x+4)=(3x+3)4 equation: 



(7x-2)+(7x-2)+(2x+4)=(3x+3)4

We move all terms to the left:

(7x-2)+(7x-2)+(2x+4)-((3x+3)4)=0

We get rid of parentheses

7x+7x+2x-((3x+3)4)-2-2+4=0



We calculate terms in parentheses: -((3x+3)4), so:

(3x+3)4

We multiply parentheses

12x+12

Back to the equation:

-(12x+12)



We add all the numbers together, and all the variables

16x-(12x+12)=0

We get rid of parentheses

16x-12x-12=0

We add all the numbers together, and all the variables

4x-12=0

We move all terms containing x to the left, all other terms to the right

4x=12

x=12/4

x=3

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