(4x-8)=(2x+28)

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Solution for (4x-8)=(2x+28) equation: 



(4x-8)=(2x+28)

We move all terms to the left:

(4x-8)-((2x+28))=0

We get rid of parentheses

4x-((2x+28))-8=0



We calculate terms in parentheses: -((2x+28)), so:

(2x+28)

We get rid of parentheses

2x+28

Back to the equation:

-(2x+28)



We get rid of parentheses

4x-2x-28-8=0

We add all the numbers together, and all the variables

2x-36=0

We move all terms containing x to the left, all other terms to the right

2x=36

x=36/2

x=18

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