(7x-19)=(2x+16)+(2x+4)

Solution for (7x-19)=(2x+16)+(2x+4) equation:

(7x-19)=(2x+16)+(2x+4)

We move all terms to the left:

(7x-19)-((2x+16)+(2x+4))=0

We get rid of parentheses

7x-((2x+16)+(2x+4))-19=0


We calculate terms in parentheses: -((2x+16)+(2x+4)), so:

(2x+16)+(2x+4)

We get rid of parentheses

2x+2x+16+4

We add all the numbers together, and all the variables

4x+20

Back to the equation:

-(4x+20)


We get rid of parentheses

7x-4x-20-19=0

We add all the numbers together, and all the variables

3x-39=0

We move all terms containing x to the left, all other terms to the right

3x=39

x=39/3

x=13