(7x+10)+(3x)+(2x+40)=180

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Solution for (7x+10)+(3x)+(2x+40)=180 equation:



(7x+10)+(3x)+(2x+40)=180
We move all terms to the left:
(7x+10)+(3x)+(2x+40)-(180)=0
We add all the numbers together, and all the variables
3x+(7x+10)+(2x+40)-180=0
We get rid of parentheses
3x+7x+2x+10+40-180=0
We add all the numbers together, and all the variables
12x-130=0
We move all terms containing x to the left, all other terms to the right
12x=130
x=130/12
x=10+5/6

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