(7x-19)+(3x-41)=180

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Solution for (7x-19)+(3x-41)=180 equation: 



(7x-19)+(3x-41)=180

We move all terms to the left:

(7x-19)+(3x-41)-(180)=0

We get rid of parentheses

7x+3x-19-41-180=0

We add all the numbers together, and all the variables

10x-240=0

We move all terms containing x to the left, all other terms to the right

10x=240

x=240/10

x=24

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