(7x-11)+(3x+41)=120

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Solution for (7x-11)+(3x+41)=120 equation: 



(7x-11)+(3x+41)=120

We move all terms to the left:

(7x-11)+(3x+41)-(120)=0

We get rid of parentheses

7x+3x-11+41-120=0

We add all the numbers together, and all the variables

10x-90=0

We move all terms containing x to the left, all other terms to the right

10x=90

x=90/10

x=9

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