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(7x-1)(4x-2)=0
We multiply parentheses ..
(+28x^2-14x-4x+2)=0
We get rid of parentheses
28x^2-14x-4x+2=0
We add all the numbers together, and all the variables
28x^2-18x+2=0
a = 28; b = -18; c = +2;
Δ = b2-4ac
Δ = -182-4·28·2
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-10}{2*28}=\frac{8}{56} =1/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+10}{2*28}=\frac{28}{56} =1/2 $
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