50=3(2b+1)-7

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Solution for 50=3(2b+1)-7 equation: 



50=3(2b+1)-7

We move all terms to the left:

50-(3(2b+1)-7)=0



We calculate terms in parentheses: -(3(2b+1)-7), so:

3(2b+1)-7

We multiply parentheses

6b+3-7

We add all the numbers together, and all the variables

6b-4

Back to the equation:

-(6b-4)



We get rid of parentheses

-6b+4+50=0

We add all the numbers together, and all the variables

-6b+54=0

We move all terms containing b to the left, all other terms to the right

-6b=-54

b=-54/-6

b=+9

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