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(7x+5)9x+3=180
We move all terms to the left:
(7x+5)9x+3-(180)=0
We add all the numbers together, and all the variables
(7x+5)9x-177=0
We multiply parentheses
63x^2+45x-177=0
a = 63; b = 45; c = -177;
Δ = b2-4ac
Δ = 452-4·63·(-177)
Δ = 46629
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{46629}=\sqrt{9*5181}=\sqrt{9}*\sqrt{5181}=3\sqrt{5181}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-3\sqrt{5181}}{2*63}=\frac{-45-3\sqrt{5181}}{126} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+3\sqrt{5181}}{2*63}=\frac{-45+3\sqrt{5181}}{126} $
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