5(q-7)-3(q-4)+4(q+2)=0

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Solution for 5(q-7)-3(q-4)+4(q+2)=0 equation: 



5(q-7)-3(q-4)+4(q+2)=0

We multiply parentheses

5q-3q+4q-35+12+8=0

We add all the numbers together, and all the variables

6q-15=0

We move all terms containing q to the left, all other terms to the right

6q=15

q=15/6

q=2+1/2

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