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(7x+5)(2x-5)=0
We multiply parentheses ..
(+14x^2-35x+10x-25)=0
We get rid of parentheses
14x^2-35x+10x-25=0
We add all the numbers together, and all the variables
14x^2-25x-25=0
a = 14; b = -25; c = -25;
Δ = b2-4ac
Δ = -252-4·14·(-25)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-45}{2*14}=\frac{-20}{28} =-5/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+45}{2*14}=\frac{70}{28} =2+1/2 $
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