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7(x-5)=5(x+3)
We move all terms to the left:
7(x-5)-(5(x+3))=0
We multiply parentheses
7x-(5(x+3))-35=0
We calculate terms in parentheses: -(5(x+3)), so:We get rid of parentheses
5(x+3)
We multiply parentheses
5x+15
Back to the equation:
-(5x+15)
7x-5x-15-35=0
We add all the numbers together, and all the variables
2x-50=0
We move all terms containing x to the left, all other terms to the right
2x=50
x=50/2
x=25
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