(7x+4)/(3x-5)=2/3

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Solution for (7x+4)/(3x-5)=2/3 equation: 



(7x+4)/(3x-5)=2/3

We move all terms to the left:

(7x+4)/(3x-5)-(2/3)=0



Domain of the equation: (3x-5)!=0

We move all terms containing x to the left, all other terms to the right

3x!=5

x!=5/3

x!=1+2/3

x∈R



We add all the numbers together, and all the variables

(7x+4)/(3x-5)-(+2/3)=0

We get rid of parentheses

(7x+4)/(3x-5)-2/3=0

We calculate fractions


(21x+12)/(9x-15)+(-6x+10)/(9x-15)=0

We multiply all the terms by the denominator


(21x+12)+(-6x+10)=0

We get rid of parentheses

21x-6x+12+10=0

We add all the numbers together, and all the variables

15x+22=0

We move all terms containing x to the left, all other terms to the right

15x=-22

x=-22/15

x=-1+7/15

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