3(k-11)=15

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Solution for 3(k-11)=15 equation: 



3(k-11)=15

We move all terms to the left:

3(k-11)-(15)=0

We multiply parentheses

3k-33-15=0

We add all the numbers together, and all the variables

3k-48=0

We move all terms containing k to the left, all other terms to the right

3k=48

k=48/3

k=16

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