(7x+3)+(2x+12)=(3x+7)

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Solution for (7x+3)+(2x+12)=(3x+7) equation: 



(7x+3)+(2x+12)=(3x+7)

We move all terms to the left:

(7x+3)+(2x+12)-((3x+7))=0

We get rid of parentheses

7x+2x-((3x+7))+3+12=0



We calculate terms in parentheses: -((3x+7)), so:

(3x+7)

We get rid of parentheses

3x+7

Back to the equation:

-(3x+7)



We add all the numbers together, and all the variables

9x-(3x+7)+15=0

We get rid of parentheses

9x-3x-7+15=0

We add all the numbers together, and all the variables

6x+8=0

We move all terms containing x to the left, all other terms to the right

6x=-8

x=-8/6

x=-1+1/3

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