(7a-4)=(3a+68)

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Solution for (7a-4)=(3a+68) equation: 



(7a-4)=(3a+68)

We move all terms to the left:

(7a-4)-((3a+68))=0

We get rid of parentheses

7a-((3a+68))-4=0



We calculate terms in parentheses: -((3a+68)), so:

(3a+68)

We get rid of parentheses

3a+68

Back to the equation:

-(3a+68)



We get rid of parentheses

7a-3a-68-4=0

We add all the numbers together, and all the variables

4a-72=0

We move all terms containing a to the left, all other terms to the right

4a=72

a=72/4

a=18

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