(7x+20)+159=(2x-5)

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Solution for (7x+20)+159=(2x-5) equation: 



(7x+20)+159=(2x-5)

We move all terms to the left:

(7x+20)+159-((2x-5))=0

We get rid of parentheses

7x-((2x-5))+20+159=0



We calculate terms in parentheses: -((2x-5)), so:

(2x-5)

We get rid of parentheses

2x-5

Back to the equation:

-(2x-5)



We add all the numbers together, and all the variables

7x-(2x-5)+179=0

We get rid of parentheses

7x-2x+5+179=0

We add all the numbers together, and all the variables

5x+184=0

We move all terms containing x to the left, all other terms to the right

5x=-184

x=-184/5

x=-36+4/5

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