(7x+2)/5=(4x-1)/2

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Solution for (7x+2)/5=(4x-1)/2 equation: 



(7x+2)/5=(4x-1)/2

We move all terms to the left:

(7x+2)/5-((4x-1)/2)=0

We calculate fractions


7x/()+(-((4x-1)*5)/()=0



We calculate terms in parentheses: +(-((4x-1)*5)/(), so:

-((4x-1)*5)/(

We multiply all the terms by the denominator


-((4x-1)*5)



We calculate terms in parentheses: -((4x-1)*5), so:

(4x-1)*5

We multiply parentheses

20x-5

Back to the equation:

-(20x-5)



We get rid of parentheses

-20x+5

Back to the equation:

+(-20x+5)



We get rid of parentheses

7x/()-20x+5=0

We multiply all the terms by the denominator


7x-20x*()+5*()=0

We add all the numbers together, and all the variables

7x-20x*()=0

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