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4x(5x+1)=0
We multiply parentheses
20x^2+4x=0
a = 20; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·20·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*20}=\frac{-8}{40} =-1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*20}=\frac{0}{40} =0 $
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