(7x+15)(2x+19)=0

Solution for (7x+15)(2x+19)=0 equation:

(7x+15)(2x+19)=0

We multiply parentheses ..

(+14x^2+133x+30x+285)=0

We get rid of parentheses

14x^2+133x+30x+285=0

We add all the numbers together, and all the variables

14x^2+163x+285=0

a = 14; b = 163; c = +285;
Δ = b2-4ac
Δ = 1632-4·14·285
Δ = 10609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10609}=103$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(163)-103}{2*14}=\frac{-266}{28}
=-9+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(163)+103}{2*14}=\frac{-60}{28}
=-2+1/7
$