4/5(10x+25)=1/3(6x-3)

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Solution for 4/5(10x+25)=1/3(6x-3) equation: 



4/5(10x+25)=1/3(6x-3)

We move all terms to the left:

4/5(10x+25)-(1/3(6x-3))=0



Domain of the equation: 5(10x+25)!=0

x∈R





Domain of the equation: 3(6x-3))!=0

x∈R



We calculate fractions


(12x6/(5(10x+25)*3(6x-3)))+(-5x1/(5(10x+25)*3(6x-3)))=0



We calculate terms in parentheses: +(12x6/(5(10x+25)*3(6x-3))), so:

12x6/(5(10x+25)*3(6x-3))

We multiply all the terms by the denominator


12x6

We add all the numbers together, and all the variables

12x^6

We do not support expression: x^6

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