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(7x+1)x2=(3x+4)x2
We move all terms to the left:
(7x+1)x2-((3x+4)x2)=0
We multiply parentheses
7x^3+x^2-((3x+4)x2)=0
We calculate terms in parentheses: -((3x+4)x2), so:
(3x+4)x2
We multiply parentheses
3x^3+4x^2
We do not support expression: x^3
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