5(b+2)+b=5(b-3)-1

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Solution for 5(b+2)+b=5(b-3)-1 equation: 



5(b+2)+b=5(b-3)-1

We move all terms to the left:

5(b+2)+b-(5(b-3)-1)=0

We add all the numbers together, and all the variables

b+5(b+2)-(5(b-3)-1)=0

We multiply parentheses

b+5b-(5(b-3)-1)+10=0



We calculate terms in parentheses: -(5(b-3)-1), so:

5(b-3)-1

We multiply parentheses

5b-15-1

We add all the numbers together, and all the variables

5b-16

Back to the equation:

-(5b-16)



We add all the numbers together, and all the variables

6b-(5b-16)+10=0

We get rid of parentheses

6b-5b+16+10=0

We add all the numbers together, and all the variables

b+26=0

We move all terms containing b to the left, all other terms to the right

b=-26

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