(7w+3)(w-1)=0

Solution for (7w+3)(w-1)=0 equation:

(7w+3)(w-1)=0

We multiply parentheses ..

(+7w^2-7w+3w-3)=0

We get rid of parentheses

7w^2-7w+3w-3=0

We add all the numbers together, and all the variables

7w^2-4w-3=0

a = 7; b = -4; c = -3;
Δ = b2-4ac
Δ = -42-4·7·(-3)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-10}{2*7}=\frac{-6}{14}
=-3/7
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+10}{2*7}=\frac{14}{14}
=1
$