(x)+(x+3)+(2x)=41

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Solution for (x)+(x+3)+(2x)=41 equation: 



(x)+(x+3)+(2x)=41

We move all terms to the left:

(x)+(x+3)+(2x)-(41)=0

We add all the numbers together, and all the variables

3x+(x+3)-41=0

We get rid of parentheses

3x+x+3-41=0

We add all the numbers together, and all the variables

4x-38=0

We move all terms containing x to the left, all other terms to the right

4x=38

x=38/4

x=9+1/2

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