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(7v-6)(2v-5)=0
We multiply parentheses ..
(+14v^2-35v-12v+30)=0
We get rid of parentheses
14v^2-35v-12v+30=0
We add all the numbers together, and all the variables
14v^2-47v+30=0
a = 14; b = -47; c = +30;
Δ = b2-4ac
Δ = -472-4·14·30
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-23}{2*14}=\frac{24}{28} =6/7 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+23}{2*14}=\frac{70}{28} =2+1/2 $
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