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(7n-3)(n-3)=0
We multiply parentheses ..
(+7n^2-21n-3n+9)=0
We get rid of parentheses
7n^2-21n-3n+9=0
We add all the numbers together, and all the variables
7n^2-24n+9=0
a = 7; b = -24; c = +9;
Δ = b2-4ac
Δ = -242-4·7·9
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-18}{2*7}=\frac{6}{14} =3/7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+18}{2*7}=\frac{42}{14} =3 $
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