x=(5*4)-(2x*(-1+2x))

Solution for x=(5*4)-(2x*(-1+2x)) equation:

x=(5*4)-(2x*(-1+2x))

We move all terms to the left:

x-((5*4)-(2x*(-1+2x)))=0

We add all the numbers together, and all the variables

x-(20-(2x*(2x-1)))=0


We calculate terms in parentheses: -(20-(2x*(2x-1))), so:

20-(2x*(2x-1))

determiningTheFunctionDomain
-(2x*(2x-1))+20


We calculate terms in parentheses: -(2x*(2x-1)), so:

2x*(2x-1)

We multiply parentheses

4x^2-2x

Back to the equation:

-(4x^2-2x)


We get rid of parentheses

-4x^2+2x+20

Back to the equation:

-(-4x^2+2x+20)


We get rid of parentheses

4x^2-2x+x-20=0

We add all the numbers together, and all the variables

4x^2-1x-20=0

a = 4; b = -1; c = -20;
Δ = b2-4ac
Δ = -12-4·4·(-20)
Δ = 321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{321}}{2*4}=\frac{1-\sqrt{321}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{321}}{2*4}=\frac{1+\sqrt{321}}{8}
$