(7k/8)-(3/4)-(5k/16)=(3/8)

Solution for (7k/8)-(3/4)-(5k/16)=(3/8) equation:

(7k/8)-(3/4)-(5k/16)=(3/8)

We move all terms to the left:

(7k/8)-(3/4)-(5k/16)-((3/8))=0

We add all the numbers together, and all the variables

(+7k/8)-(+5k/16)-(+3/4)-((+3/8))=0

We get rid of parentheses

7k/8-5k/16-3/4-((+3/8))=0

We calculate fractions


(-5120k^2)/()+1792k/()+()/()+()/()=0

We add all the numbers together, and all the variables

(-5120k^2)/()+1792k/()+2=0

We multiply all the terms by the denominator


(-5120k^2)+1792k+2*()=0

We add all the numbers together, and all the variables

(-5120k^2)+1792k=0

We get rid of parentheses

-5120k^2+1792k=0

a = -5120; b = 1792; c = 0;
Δ = b2-4ac
Δ = 17922-4·(-5120)·0
Δ = 3211264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3211264}=1792$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1792)-1792}{2*-5120}=\frac{-3584}{-10240}
=7/20
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1792)+1792}{2*-5120}=\frac{0}{-10240}
=0
$