12x2+48x+45=0

Solution for 12x2+48x+45=0 equation:

12x^2+48x+45=0

a = 12; b = 48; c = +45;
Δ = b2-4ac
Δ = 482-4·12·45
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-12}{2*12}=\frac{-60}{24}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+12}{2*12}=\frac{-36}{24}
=-1+1/2
$