(7k+2)-(4k+3)=(2k+6)-(4k+3)

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Solution for (7k+2)-(4k+3)=(2k+6)-(4k+3) equation: 



(7k+2)-(4k+3)=(2k+6)-(4k+3)

We move all terms to the left:

(7k+2)-(4k+3)-((2k+6)-(4k+3))=0

We get rid of parentheses

7k-4k-((2k+6)-(4k+3))+2-3=0



We calculate terms in parentheses: -((2k+6)-(4k+3)), so:

(2k+6)-(4k+3)

We get rid of parentheses

2k-4k+6-3

We add all the numbers together, and all the variables

-2k+3

Back to the equation:

-(-2k+3)



We add all the numbers together, and all the variables

3k-(-2k+3)-1=0

We get rid of parentheses

3k+2k-3-1=0

We add all the numbers together, and all the variables

5k-4=0

We move all terms containing k to the left, all other terms to the right

5k=4

k=4/5

k=4/5

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