(x-5)=(x+4)/2

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Solution for (x-5)=(x+4)/2 equation: 



(x-5)=(x+4)/2

We move all terms to the left:

(x-5)-((x+4)/2)=0

We get rid of parentheses

x-((x+4)/2)-5=0

We multiply all the terms by the denominator


x*2)-((x+4)-5*2)=0

We add all the numbers together, and all the variables

x*2)-((x+4)=0

Wy multiply elements

2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$

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