(7/6)(6p-24)+9=23

Solution for (7/6)(6p-24)+9=23 equation:

(7/6)(6p-24)+9=23

We move all terms to the left:

(7/6)(6p-24)+9-(23)=0


Domain of the equation: 6)(6p-24)!=0

p∈R


We add all the numbers together, and all the variables

(+7/6)(6p-24)+9-23=0

We add all the numbers together, and all the variables

(+7/6)(6p-24)-14=0

We multiply parentheses ..

(+42p^2+7/6*-24)-14=0

We multiply all the terms by the denominator


(+42p^2+7-14*6*-24)=0

We get rid of parentheses

42p^2+7-24-14*6*=0

We add all the numbers together, and all the variables

42p^2=0

a = 42; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·42·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{0}{84}=0$