2(4-2r)-5=-2(r+5)=8r

Solution for 2(4-2r)-5=-2(r+5)=8r equation:

2(4-2r)-5=-2(r+5)=8r

We move all terms to the left:

2(4-2r)-5-(-2(r+5))=0

We add all the numbers together, and all the variables

2(-2r+4)-(-2(r+5))-5=0

We multiply parentheses

-4r-(-2(r+5))+8-5=0


We calculate terms in parentheses: -(-2(r+5)), so:

-2(r+5)

We multiply parentheses

-2r-10

Back to the equation:

-(-2r-10)


We add all the numbers together, and all the variables

-4r-(-2r-10)+3=0

We get rid of parentheses

-4r+2r+10+3=0

We add all the numbers together, and all the variables

-2r+13=0

We move all terms containing r to the left, all other terms to the right

-2r=-13

r=-13/-2

r=6+1/2