(7/3)-(3/(x-5))=(19/12)

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Solution for (7/3)-(3/(x-5))=(19/12) equation: 


D( x )

x-5 = 0

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

x in (-oo:5) U (5:+oo)

7/3-(3/(x-5)) = 19/12 // - 19/12

7/3-(3/(x-5))-(19/12) = 0

7/3-3*(x-5)^-1-19/12 = 0

7/3-3/(x-5)-19/12 = 0

(-3*3*12)/(3*12*(x-5))+(7*12*(x-5))/(3*12*(x-5))+(-19*3*(x-5))/(3*12*(x-5)) = 0

7*12*(x-5)-19*3*(x-5)-3*3*12 = 0

84*x-57*x-528+285 = 0

27*x-243 = 0

(27*x-243)/(3*12*(x-5)) = 0

(27*x-243)/(3*12*(x-5)) = 0 // * 3*12*(x-5)

27*x-243 = 0

27*x-243 = 0 // + 243

27*x = 243 // : 27

x = 243/27

x = 9

x = 9

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