(7/3)-(3/x-5)=19/12

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Solution for (7/3)-(3/x-5)=19/12 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

7/3-(3/x)+5 = 19/12 // - 19/12

7/3-(3/x)-(19/12)+5 = 0

7/3-3*x^-1-19/12+5 = 0

-3*x^-1 = -23/4 // : -3

x^-1 = 23/12

-1 < 0

1/(x^1) = 23/12 // * x^1

1 = 23/12*x^1 // : 23/12

12/23 = x^1

x = 12/23

x = 12/23

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