(7/2x-3)+(3/x+2)=(6/2x-3)

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Solution for (7/2x-3)+(3/x+2)=(6/2x-3) equation: 



(7/2x-3)+(3/x+2)=(6/2x-3)

We move all terms to the left:

(7/2x-3)+(3/x+2)-((6/2x-3))=0



Domain of the equation: 2x-3)!=0

x∈R





Domain of the equation: x+2)!=0

x∈R





Domain of the equation: 2x-3))!=0

x∈R



We get rid of parentheses

7/2x+3/x-((6/2x-3))-3+2=0

We calculate fractions

We do not support expression: x^3

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