-4(u+3)=2u-3+3(3u+3)

Solution for -4(u+3)=2u-3+3(3u+3) equation:

-4(u+3)=2u-3+3(3u+3)

We move all terms to the left:

-4(u+3)-(2u-3+3(3u+3))=0

We multiply parentheses

-4u-(2u-3+3(3u+3))-12=0


We calculate terms in parentheses: -(2u-3+3(3u+3)), so:

2u-3+3(3u+3)

determiningTheFunctionDomain
2u+3(3u+3)-3

We multiply parentheses

2u+9u+9-3

We add all the numbers together, and all the variables

11u+6

Back to the equation:

-(11u+6)


We get rid of parentheses

-4u-11u-6-12=0

We add all the numbers together, and all the variables

-15u-18=0

We move all terms containing u to the left, all other terms to the right

-15u=18

u=18/-15

u=-1+1/5