(7/(2n+4))+(5/(3n-6))=5

Solution for (7/(2n+4))+(5/(3n-6))=5 equation:

(7/(2n+4))+(5/(3n-6))=5

We move all terms to the left:

(7/(2n+4))+(5/(3n-6))-(5)=0


Domain of the equation: (2n+4))!=0

n∈R



Domain of the equation: (3n-6))!=0

n∈R


We calculate fractions


(21n-42)/((2n+4))*3n+(10n+20)/((2n+4))*3n-5=0

We multiply all the terms by the denominator


(21n-42)+(10n+20)-5*((2n+4))*3n=0

We get rid of parentheses

21n+10n-5*((2n+4))*3n-42+20=0

We add all the numbers together, and all the variables

31n-5*((2n+4))*3n-22=0

We move all terms containing n to the left, all other terms to the right

31n-5*((2n+4))*3n=22